THE OUTPUT WOULD BE
#include<stdio.h>
#include<conio.h>
void main( )
{ clrscr( );
float X,Y,a1,b1,c1,a2,b2,c2;
printf("The Standard form of equation are : aX+bY+c=0");
printf("\nEnter the value of a1,b1,c1=\n");
scanf("\t%f\t%f\t%f",&a1,&b1,&c1);
printf("Enter the value of a2,b2,c2=\n");
scanf("\t%f\t%f\t%f",&a2,&b2,&c2);
if(a1/a2!=b1/b2)
{ X=((b1*c2-b2*c1)/(a1*b2-a2*b1));
Y=((c1*a2-c2*a1)/(a1*b2-a2*b1));
printf("Unique solution and Intersect at a point\n");
printf("The value of X=%.2f",X);
printf("\tThe value of Y=%.2f",Y);
}
if(a1/a2==b1/b2 && b1/b2==c1/c2)
{ printf("Infinite number of solution and Coincident");
}
if(a1/a2==b1/b2 && b1/b2!=c1/c2)
{ printf("No solution and Parallel");
}
getch( );
}
#include<stdio.h>
#include<conio.h>
void main( )
{ clrscr( );
float X,Y,a1,b1,c1,a2,b2,c2;
printf("The Standard form of equation are : aX+bY+c=0");
printf("\nEnter the value of a1,b1,c1=\n");
scanf("\t%f\t%f\t%f",&a1,&b1,&c1);
printf("Enter the value of a2,b2,c2=\n");
scanf("\t%f\t%f\t%f",&a2,&b2,&c2);
if(a1/a2!=b1/b2)
{ X=((b1*c2-b2*c1)/(a1*b2-a2*b1));
Y=((c1*a2-c2*a1)/(a1*b2-a2*b1));
printf("Unique solution and Intersect at a point\n");
printf("The value of X=%.2f",X);
printf("\tThe value of Y=%.2f",Y);
}
if(a1/a2==b1/b2 && b1/b2==c1/c2)
{ printf("Infinite number of solution and Coincident");
}
if(a1/a2==b1/b2 && b1/b2!=c1/c2)
{ printf("No solution and Parallel");
}
getch( );
}
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